xuan oanh Huynh edited untitled.tex  almost 8 years ago

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\end{table}\\  12) (e$\wedge$p)$\rightarrow$m\\  16)\\  a) q$\ringtarrow$p\\ q$\rightarrow$p\\  b) q$\wedge$$\neg$p\\  c) q$\rightarrow$p\\  d) $\neg$q$\rightarrow$$\neg$p\\  \section(Chapter \section{Chapter  2 solution:)\\ solution:}\\  4)\\  a. Q(0) means that 0+1 > 2*x, which would mean that 1 > 0. This is true.\\  b. Q(-1) means that -1+1 > 2*-1, which means that 0 > -2. This is true.\\