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q $\rightarrow$ r\\  $\therefore$ p $\rightarrow$ r  \end{center}\\  14)Thee 14)The  premise is "Someone is happy", it is not said the exactly the name of that person so we can not say that is Lola or someone else, and we do not know that Lola is in the domain or not.\\ 16)\\  Let a and b be odd integers. By definition of odd we have that a = 2n + 1 and b = 2m + 1. Consider the sum a + b = (2n + 1) + (2m +1) = 2n + 2m +2 = 2k, where k = n + m + 1 is an integer. Therefore by definition of even we have shown that a + b is even.\\  17)\\