this is for holding javascript data
J. A. Hernandez edited sectionClique_width_.tex
almost 8 years ago
Commit id: 488569ab8211bc8ec2ee33e7205e6c2546d101ed
deletions | additions
diff --git a/sectionClique_width_.tex b/sectionClique_width_.tex
index 59ba97f..896ad3f 100644
--- a/sectionClique_width_.tex
+++ b/sectionClique_width_.tex
...
\section{Clique width for paths}
For a graph $P_{2}$, and $P_{3}$ the \emph{cwd }is $2$.
\begin{example}
Now we show the result of compute the \emph{cwd} of a $P_{4}$. Let
$G=(\text{\{}v_{1},v_{2},v_{3},v_{4}\},\{v_{1}v_{2},v_{2}v_{3},v_{3}v_{4}\})$.
The resulting $k$-expression is:
\end{example}
$\rho_{c\rightarrow a}(\eta_{c,b}(\rho_{b\rightarrow a}(\eta_{b,c}(\eta_{a,b}(a\oplus b)\oplus c))\oplus b))$,
therefore the $cwd\leq3$.
\begin{prop}
The $cwd(P_{n})\leq3$.
\end{prop}
\begin{proof}
By induction on the structure.
If $P_{1}$ is a path with just one label, the $k$-expression is
$a$ and the $cwd(P_{1})$ is $1$, therefore the proposition holds.
Now we assume for a path $P_{n}$ there is a $k$-expression such
that the $cwd(P_{n})\leq3$. To show for $P_{n+1}$ there is a $k$-expression
such that the $cwd(P_{n+1})\leq3$. By construction we assume that
the label of the last vertex of $P_{n}$ is different from the others
i.e the label $b$, that means that $a$ is the label of the remaining
$n-1$ vertices.
The $3$-expression that constructs a path of length $n+1$ is the
following:
%$\rho_{c\rightarrow b}(\rho_{b\rightarrow a}(\eta_{b,c}((3-$expression$_{P_{n}})\oplus c)))$.
\end{proof} \section{A}