deletions | additions       diff --git a/scattering 2.tex b/scattering 2.tex  index b07cefd..9fab05b 100644  --- a/scattering 2.tex  +++ b/scattering 2.tex 
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Therefore, we can conclude the following: the resistivity, inversely proportional to the conductivity, has the following behaviour:  \begin{equation}  \begin{split} \rho &= =  \rho_\mathrm{impurity} + A_\textrm{qp-qp} &T^2 \quad T \ll T_F \\ \end{equation}   \begin{equation}  \rho &= =  \rho_\mathrm{impurity} + B_\textrm{qp-ph} &T \quad T \gg T_F\end{split}  \end{equation}