deletions | additions       diff --git a/section_Solutions_and_hints_for__.tex b/section_Solutions_and_hints_for__.tex  index cfa1a8f..244276a 100644  --- a/section_Solutions_and_hints_for__.tex  +++ b/section_Solutions_and_hints_for__.tex 
...
\item $1 \cdot (0 + 1) + 0 \cdot (1 + 1)= (1\cdot 0)+(1\cdot 1)+(0\cdot 1)+(0\cdot 1)= 0+1+0+0=1$  \end{itemize}  \textbf{Exercise 5.}  \\  First of all, we notice that XOR behaves as the sum of bits, whereas AND behaves as multiplication.\\  We cannot say the same for OR. Moreover:  \begin{itemize}  \item $\textrm{NOT }((\textrm{NOT }a) \textrm{ AND }(\textrm{NOT }b)) = a\textrm{ OR }b$  \item $\textrm{NOT }((\textrm{NOT }a)\textrm{ OR }(\textrm{NOT }b)) = a\textrm{ AND }b$