this is for holding javascript data
Michela Ceria edited bits3.tex
about 8 years ago
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We notice the following facts:
\begin{itemize}
\item performing the algorithm a finite number of times we get again the initial vectore $(1,0,1)$
\item
there are only the numbers $1,2,3,4,5,6,7$ can be written using three bits not all zero and, performing the algorithm, we found all these numbers. This is not true in general. The feedback polynomials for which this property holds is called \emph{primitive}.
\end{itemize}
\begin{Example}
We see now an example of non primitive polynomial. Let us consider $f(x)=x^3+1$ and we start again from $(1,0,1)$
\begin{center}
\begin{tabular}{ |c || c | c | c |}
\hline
1&1 & 0& 1 \\
\hline
\end{tabular}
\end{center}
\begin{center}
\begin{tabular}{ |c || c | c | c |}
\hline
?&1 & 1& 0 \\
\hline
\end{tabular}
\end{center}
then
\begin{center}
\begin{tabular}{ |c || c | c | c |}
\hline
0&1 & 0& 1 \\
\hline
\end{tabular}
\end{center}
\begin{center}
\begin{tabular}{ |c || c | c | c |}
\hline
?&0 & 1& 0 \\
\hline
\end{tabular}
\end{center}
\end{Example}
\begin{center}
\begin{tabular}{ |c || c | c | c |}
\hline
0&0 & 1& 0 \\
\hline
\end{tabular}
\end{center}
\begin{center}
\begin{tabular}{ |c || c | c | c |}
\hline
?&0 & 0& 1 \\
\hline
\end{tabular}
\end{center}
\begin{center}
\begin{tabular}{ |c || c | c | c |}
\hline
1&0 & 0& 1 \\
\hline
\begin{center}
\begin{tabular}{ |c || c | c | c |}
\hline
?&1 & 0& 0 \\
\hline
\end{tabular}
\end{center}
\begin{center}
\begin{tabular}{ |c || c | c | c |}
\hline
?&0 & 1& 0 \\
\hline
\end{tabular}
\end{center}
\end{Example}
\end{tabular}
\end{center}
\end{Example}
\begin{center}
\begin{tabular}{ |c || c | c | c |}
\hline
?&0 & 1& 0 \\
\hline
\end{tabular}
\end{center}
\end{Example}
Primitive polynomials are irreducible but the vice versa does not hold. For example, the polynomial $x^4 + x^3 + x^2 + x + 1$ is irreducible but it is not primitive.
\begin{Exercise}
Verify that $x^4 + x^3 + x^2 + x + 1$ is not primitive via a LFSR.
\end{Exercise}