Michela Ceria edited section_Solutions_and_hints_for__.tex  about 6 years ago

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$(x+1)^4 = x^4+4x^3+6x^2+4x+1\rightarrow \mathbf{1\;4\;6\; 4\;1}$\\  and so on.  \\  We have then the Pascal's (Tartaglia's!) Triangle:  \begin{equation}   1\\  1\; 1\\  1\;2\;1\\  1\;3\;3\;1\\  1\;4\;6\; 4\;1  \end{equation} We can notice that if in the in the Pascal's Triangle we have