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\section{$n^{th}$-order decay, $n\,A\to P$}  We now shift our attention to $n^{th}$ order reactions. These $n^{th}$ order reactions are of the form of one reactant turning into product. The inequality between the statistical length and divergence can also be derived for these irreversible decay reactions. The time dependent rate coefficient is  \begin{equation}  k_n(t)  \equiv \frac{d}{dt}\frac{1}{S(t)^{n-1}}  = (n-1)\omega C_A(0)^{n-1}  \end{equation}  As shown in equation 4, the statistical length is the integral of the cumulative time dependent rate coefficient over a period of time $\Delta{t}$. The statistical length is   \begin{equation}  \mathcal{L}_n(\Delta t)^2 = \left[\int_{t_i}^{t_f}(n-1)\omega([A_0]^{n-1})dt\right]^2   \end{equation}  Following length, the Fisher divergence is the integral of the cumulative time dependent rate coefficient squared over a period of time $\Delta{t}$. The Fisher divergence is  \begin{equation}  \frac{\mathcal{J}_n(\Delta t)}{\Delta t} = \int_{t_i}^{t_f}{(n-1)^2\omega^2}([A_0]^{n-1})^{2} dt  \end{equation}  Both the length squared and the divergence are $(n-1)^2\omega^2([A_0]^{n-1})^2\Delta t^2$: the bound holds when there is no static or dynamic disorder, and a single rate coefficient is sufficient for the irreversible decay process. The nonlinearity of the rate law leads to solutions that depend on concentration. This concentration dependence is also present in both $\mathcal{J}$ and $\mathcal{L}$.         

Introduction.tex  Nonlinear irreversible kinetics.tex  Second-order decay.tex  $n^{th}$-order decay.tex  Kinetic model with dynamic disorder.tex  Kinetic model with static disorder.tex  figures/scheme/scheme.png