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Jason R. Green edited Second-order decay.tex
over 9 years ago
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\begin{equation}
k_2(t) \equiv \frac{d}{dt}S(t)^{-1} = \omega C_A(0)
\end{equation}
$S(t)$ has been changed to fit a second order model of irreversible decay. From this definition of $k(t)$, we define a statistical distance. The statistical distance represents the distance between two different probability distributions, which can be applied to survival functions and rate coefficients.[cite] Integrating the arc length of the survival curve , $\frac{1}{S(t)}$, gives the statistical
length.
\begin{equation} length
%\begin{equation}
% \mathcal{L}(\Delta{t})^2=\left[\int_{t_i}^{t_f}k(t)dt\right]^2
\end{equation}
Which is equal to $\frac{1}{S(t)}\big|_{S_(t_f)}^{S_(t_i)}$, %\end{equation}
$\mathcal{L}_2(\Delta{t})\frac{1}{S(t)}\big|_{S_(t_f)}^{S_(t_i)}$, which measures the cumulative rate coefficient, same as in first order irreversible decay. As seen in first order, the statistical length is also dependent on the time interval, with the statistical length being infinite in an infinite time interval.
In first order irreversible decay, the inequality between the statistical length squared and Fisher divergence determines when a rate coefficient is constant, which is only when the inequality turns into an equality.[cite] A similar inequality is found in second order kinetics.
Putting in the time dependent rate coefficient for a second order irreversible decay, the inequality becomes
\begin{equation}