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\section{Mixed second-order decay, $A+B\to P$}  Second order reactions can also occur in the form of two different molecules combining into products irreversibly. Determining when the rate coefficient of a mixed second order reaction is constant is possible, and is able to be done without survival functions. Survival functions were not used in the case of mixed second order decay because the integrated rate law only allows the survival function of one reactant to be looked at at a time. This is true as long as the initial concentrations of both reactants are not equal. If the initial concentration of both reactants is equal, then the concentration of both reactants will be equal to each other at all times, and the mixed second order reaction can be treated as a regular second order reaction, leading to the inequality in equation 19. The rate law for a mixed second order reaction is  \begin{equation}  \int\frac{dx}{([A_0]-x)([B_0]-x)}=k(t)