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Vadim Kosoy edited The_following_theorem_is_the__.tex
about 8 years ago
Commit id: f04022e4feaaff3cd6a84673ffe1047b65a8e75f
deletions | additions
diff --git a/The_following_theorem_is_the__.tex b/The_following_theorem_is_the__.tex
index 1feddd8..3e2cb2b 100644
--- a/The_following_theorem_is_the__.tex
+++ b/The_following_theorem_is_the__.tex
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\begin{proof}
Fix $S: \Words \xrightarrow{\Gamma} \Rats$ with $\R_S \geq \R_P$. Consider
$t := \sigma 2^{-a}$ where $\sigma \in any $\sigma: \Nats^2 \rightarrow \{ \pm 1 \}$ and
$a \in $n: \Nats^2 \rightarrow \Nats$.
Define $t(k,j) := \sigma(k,j) 2^{-n(k,j)}$. Choose $h: \Nats^2 \rightarrow \Nats$ a polynomial s.t. $2^{-h} \in \mathcal{E}$.
Define $Q: Then, there is $Q_t: \Words \xrightarrow{\Gamma} \Rats$ s.t. given $k,j \in \Nats$, $x \in \Supp \mu^k$, $y \in \WordsLen{\R_P(k,j)}$ and $z \in \WordsLen{\R_P(k,j) - \R_S(k,j)}$, $\Abs{Q^{kj}(x,yz) - (P^{kj}(x,y) +
t t(k,j) S^{kj}(x,yz))} \leq 2^{-h(k,j)}$.
$$ E_{\mu^k \times U^{r(k,j)}}[(P^{kj}-f)^2] \leq E_{\mu^k \times U^{r(k,j)} \times U^s}[(R-f)^2] + \tilde{\delta}(k,j,T_R^\mu(k,r(k,j)+s),2^{|R|}) $$