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Shane Flynn edited Absolute Formulation.tex
over 9 years ago
Commit id: f62cd51bf66ef901e4658895ab39a5c85cc43294
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diff --git a/Absolute Formulation.tex b/Absolute Formulation.tex
index 84ceab9..78e7531 100644
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\begin{equation}
GFE_a=\frac{d}{dt}\sum [\gamma_i(t)k_a(t)]
\end{equation}
We also know that $k_a\equiv \frac{d}{dt}[\ln S_i]$ and that $\gamma_i=\frac{S_i}{\sum[S_i]}$. With these definition we can determine the time derivative of the average rate as follows.
\begin{equation}
\frac{d}{dt}\sum [\gamma_i(t)k_a(t)]=\sum[\frac{d}{dt}[\gamma_i(t)k_a(t)]]
\end{equation}
Now applying the product rule and distributing the sum we find the following.
\begin{equation}
GFE_a=\sum[\gamma_i\frac{d}{dt}[k_a]]+\sum[k_a\frac{d}{dt}[\frac{S_i}{\sum[S_i]}]]
\end{equation}
The second term can be evaluated and simplified using the product rule for the derivative as follows.
\begin{equation}
GFE_a=\sum[\gamma_i\frac{d}{dt}[k_a]]+\sum[k_a(S_i\frac{d}{dt}[(\Sigma[S_i])^{-1}]+(\Sigma[S_i])^{-1}\frac{d}{dt}[S_i])]
\end{equation}
Simplifying further we find
\begin{equation}
GFE_a=\sum[\gamma_i\frac{d}{dt}[k_a]]+\sum[k_a(\frac{-S_i}{(\Sigma S_i)^2}\frac{d}{dt}[(\Sigma S_i)]+(\Sigma S_i)^{-1}\frac{d}{dt}[S_i])]