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Andrew Magalich added Now_consider_2_observes_stationary__.tex
almost 8 years ago
Commit id: c6e418b9b017b3482a63ac1a0c0e6714c596adeb
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Now, consider 2 observes stationary at the radii $R_1$ and $R_2$. For each of them $\frac{d\vec{x}}{d\tau} = 0$. From the normalization of 4-velocity, it follows that
$$
\frac{dx^\mu}{d\tau} \frac{dx_\mu}{d\tau} = -1
$$
$$
\dot{t}^2 = \left(1-\frac{2M}{r}\right)^{-1}
$$
