Christine Perez edited According_to_citet_To_2013_the__.tex  about 8 years ago

Commit id: bbdc508183717a909bfa882cac2ffbf0381f0f91

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\begin{equation*}y_{height}=(v_{0y}\sin\theta)t-\frac{1}{2}gt^{2}+y_{start},\tag{1}\end{equation*}  where y start is the initial starting height from which the garbage will be thrown from the angle theta, and y height being the maximum height the garbage can reach in time t while g is the acceleration due to the gravity of the earth which is 9.8m/s^2 and,  \begin{equation*}R\quad =\quad \frac { { { v }_{ start } }^{ 2 }sin2\theta }{ g },\tag{2}\end{equation*}  where v start is the initial velocity, sin theta as the component along the y-axis, and g being the acceleration due to gravity which is 9.8 m/s^2.