Austin Warby edited Yep_sqrt_5__.tex  about 8 years ago

Commit id: 9f9532a7fd5c9298cfe89f4343c3baba9de3aeaa

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Yep  $\sqrt{5}$ $F_n=\frac{1}{\sqrt{5}}\left(\left(\frac{1+\sqrt{5}}{2}\right)^n-\left(\frac{1-\sqrt{5}}{2}\right)^n\right)$