Terris Becker edited untitled.tex  almost 8 years ago

Commit id: 0cc57bf82e016270c9474c9f94ba3436197c560a

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&= \frac{2\pi i}{2i(\sqrt2 +i\sqrt2)}\\  &= \frac{2\pi i}{2i\sqrt2-2\sqrt2}\\  &=\frac{\pi i}{-\sqrt2+i\sqrt2}\\  \end{align*}  And now for the integral over $\gamma_2$.  \begin{align*}  \int_{\gamma_1}\frac{dz}{z^{4}+1} &= \int_{\gamma_1}\frac{dz}{(z-(\frac{\sqrt2}{2}+i\frac{\sqrt2}{2}))(z-(-\frac{\sqrt2}{2}+i\frac{\sqrt2}{2}))(z-(-\frac{\sqrt2}{2}-i\frac{\sqrt2}{2}))(z-(\frac{\sqrt2}{2}-i\frac{\sqrt2}{2}))}\\  &= \int_{\gamma_1}\frac{\frac{dz}{(z-(-\frac{\sqrt2}{2}+i\frac{\sqrt2}{2}))(z-(-\frac{\sqrt2}{2}-i\frac{\sqrt2}{2}))(z-(\frac{\sqrt2}{2}-i\frac{\sqrt2}{2}))}}{(z-(\frac{\sqrt2}{2}+i\frac{\sqrt2}{2}))}  \end{align*}