Terris Becker edited untitled.tex  about 8 years ago

Commit id: b0423f0dcb60ec85bc7b551de3a2c10986891931

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\begin{align*}  z^{n}&=re^{i\theta}\\  &=re^{i\theta}e^{(2\pi m)i}\text{ For $m\in\mathbb{N}$}\\  &=re^{i(\theta+2\pi m)}\\ m)}  \end{align*}  Thus,  \begin{align*}