Terris Becker edited untitled.tex  about 8 years ago

Commit id: 024ebed1c11d94eb01ad2a208e3c26f2210ed031

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\begin{align*}  z=\sqrt[n]{z^{n}}=\sqrt[n]{r}e^{\frac{i(\theta+2\pi m)}{n}}  \end{align*}  Note that $m\leq n$ because if $m\gt n$, $m>n$,  then $m=n+k$ for some positive integer $k$.\\ Then,   \begin{align*}  e^{\frac{i(\theta+2\pi m)}{n}} &=e^{\frac{i\theta}{n}}e^{\frac{i2\pi (n+k)}{n}}\\