Terris Becker edited untitled.tex  about 8 years ago

Commit id: dc54e762fd22eaf7aba90709c93c2b3dd0dd3b60

deletions | additions      

       

The above equation is a circle with radius $r=\sqrt{\frac{1}{4}(d^{2}+e^{2})}$, so $r^{2}$ must be greater than or equal to zero in order for a solution to exist. Thus,  \begin{align}  \frac{1}{4}(d^{2}+e^{2}\geq0  \end{align}  \end{proof}