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Terris Becker edited untitled.tex
about 8 years ago
Commit id: 41b94dd146a40a9fc8b6399e5bcb222c812b5bb7
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\begin{proof}\textit{Proof:} Let $a\in\mathbb{C}$,$b\in\mathbb{R}$, and $z\in\mathbb{C}$.\\
Then $a=d+ei$ and $z=f+gi$ for some $d,e,f,g\in\mathbb{R}$.\\
Note that:
\begin{align}
|z^{2}|=z\overline z=f^{2}+g^{2}\\
\text{and}\\
Re(az)=fd-eg
\end{align} $$|z^{2}|=z\overline z=f^{2}+g^{2}$$\\
and
$$Re(az)=fd-eg$$
So $|z^{2}|+Re(az)+b=0$ has solutions if and only if $(f^{2}+g^{2})+(fd-eg)+b=0$
because $|z^{2}|=z\overline z$
\end{proof}