Veva Garcia edited untitled.tex  about 8 years ago

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=2\pi i (-\frac{1}{6})\\  = \frac{-\pi i}{3}\\  \end{align*}  Hence, $\int_{c[-2,3]} $$\int_{c[-2,3]}  \frac{dz}{z^2-2z-8}=\frac{-\pi i}{3}$ i}{3}$$  By Theorem 4.23 (Cauchy's Theorem): if f is holomorphic in $\mathbb{C}\setminus\left\{-2\right\}$ and $C[0,3] ~\mathbb{C}\setminus\left\{-2\right\} C[-2,3]$