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Veva Garcia edited untitled.tex
almost 8 years ago
Commit id: a519149ff7195cf3ff3a3c253506fd3d09866e09
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To solve for $\theta$, we have $n\theta= \theta +2\pi k$, for some $k\in\mathbb{Z}$ \\
Then $\theta=\frac{\theta + 2 \pi k}{n}$\\
Therefore we have $z=\sqrt[n]{r}e^{i\frac{\theta +2 \pi k}{n}}$
By the Fundamental Theorem of Algebra, there are n solutions
\end{proof}
\end{problem}