Veva Garcia edited untitled.tex  almost 8 years ago

Commit id: 1d9d3fe17f0ffe5a11446d09833d13a3936d2597

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To solve for $\theta$, we have $n\theta= \theta +2\pi k$, for some $k\in\mathbb{Z}$ \\  Then $\theta=\frac{\theta + 2 \pi k}{n}$\\  Therefore we have $z=\sqrt[n]{r}e^{i\frac{\theta +2 \pi k}{n}}$  By the Fundamental Theorem of Algebra, there are n solutions to $z^n =w$ =w.$  \end{proof}  \end{problem}