this is for holding javascript data
Veva Garcia edited untitled.tex
about 8 years ago
Commit id: e95b7ffbbb6c19224323e52f15a4bb5a0d19ef6e
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$\Leftrightarrow (x^2+cx) +(y^2-dy) +b =0$\\
$\Leftrightarrow (x+\frac{1}{2}c)^2 + (y-\frac{1}{2}d)^2 = -b + \frac{1}{4}(c^2+d^2)$ by completing the square\\
The equation above is a circle with a radius of $\sqrt{-b + \frac{1}{4}(c^2+d^2)}.$\\
$r^2$ must be greater or equal to zero, for a solution to exist, so
$-b + \frac{1}{4}(c^2+d^2) \geq 0$