Veva Garcia edited untitled.tex  about 8 years ago

Commit id: d6a95bb9e4038f69c3088d8b7904434e7537a1c3

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$\Leftrightarrow x^2+y^2 + Re(cx-dy+i(dx+cy))+b=0$\\  $\Leftrightarrow x^2 +y^2 + cx-dy + b=0$\\  $\Leftrightarrow (x^2+cx) +(y^2-dy) +b =0$\\  $\Leftrightarrow (x+\frac{1}{2}c)^2 + (y-\frac{1}{2}d)^2 = -b + \frac{1}{4}(c^2+d^2)$\\ \frac{1}{4}(c^2+d^2)$ by completing the square\\