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Veva Garcia edited untitled.tex
about 8 years ago
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Fix $a \in \mathbb{C}$ and $b \in \mathbb{R}.$ Show that the equation $\left|z^2\right|+Re(az)+b=0$ has a solution if and only if
$\left|a^2 \right| \geq 4b.$ When solutions exist, show the solution set is a circle.