Veva Garcia edited untitled.tex  about 8 years ago

Commit id: 0aee6c52b27eacc03b13ff0275e122f79c2d46ac

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$\Leftrightarrow x^2 +y^2 + cx-dy + b=0$\\  $\Leftrightarrow (x^2+cx) +(y^2-dy) +b =0$\\  $\Leftrightarrow (x+\frac{1}{2}c)^2 + (y-\frac{1}{2}d)^2 = -b + \frac{1}{4}(c^2+d^2)$ by completing the square\\  The equation above is a circle with a radius of $\sqrt{-b + \frac{1}{4}(c^2+d^2) \frac{1}{4}(c^2+d^2)$