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Stepan Salov edited section_addcontentsline_toc_section_x__.tex
almost 8 years ago
Commit id: 4a61438e48fca06e3f3d015b76b8be124b2cb30a
deletions | additions
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\begin{equation}
e(t+1)=x(t+1)-xOpt(t+1)
\end{equation}
Подставляем в уравнение
$1$ $(1)$ выражение
$2$ $(2)$ и упрощаем:
$$
e(t+1)=x(t+1)–K_{t+1}\cdot z(t+1)-(1-K_{t+1})\cdot (xOpt(t)+a\cdot t+2.1)=\\=x(t+1)-K_{t+1}\cdot (x(t+1)+N_{t+1})-(1-K_{t+1})\cdot (xOpt(t)+a\cdot t+2.1)=\\=x(t+1)\cdot (1-K_{t+1})-K_{t+1}\cdot (x(t+1)+N_{t+1})-(1-K_{t+1})\cdot (xOpt(t)+a\cdot t+2.1)=\\=(1-K_{t+1})\cdot (x(t+1)–xOpt(t)–a\cdot t–2.1)–K_{t+1}\cdot N_{t+1}=\\=(1-K_{t+1})\cdot (x(t)+a\cdot t+2.1+E_{t}–xOpt(t)–a\cdot t–2.1)–K_{t+1}\cdot N_{t+1}=\\=(1-K_{t+1})\cdot (x(t)–xOpt(t)+E_{t})–K_{t+1}\cdot N_{t+1}=\\=(1-K_{t+1})\cdot (e(t)+E_{t})–K_{t+1}\cdot N_{t+1}$$
Таким образом, получаем: