this is for holding javascript data
Ask Hjorth Larsen edited figures/fig-cs-potential/caption.tex
over 9 years ago
Commit id: fb6c95700b8508c1c6b7fccf7408368f2c66b020
deletions | additions
diff --git a/figures/fig-cs-potential/caption.tex b/figures/fig-cs-potential/caption.tex
index a8a1b0c..35fdd17 100644
--- a/figures/fig-cs-potential/caption.tex
+++ b/figures/fig-cs-potential/caption.tex
...
Replace The parameter $\theta$ is a fixed number that one must choose, with
the original theorems proven for $0<\theta<\pi/4$. The spatial coordinates $\ve
r$ are rotated to $\ve r \ee^{\ii\theta}$ in the complex plane, and one
hence works in terms of the analytic continuations of both states and
operators. The idea of complex scaling is that for suitable $\theta$,
the analytic continuation of the Siegert states are \emph{localized}
instead of diverging,
and are eigenstates of the non-Hermitian
operator $\hat H_\theta$. Importantly, matrix elements (and in
particular energies) of states are independent of $\theta$ as long as
the states are localized and well presented numerically --- this
ensures all physical
bound-state characteristics of the untransformed Hamiltonian are retained.
A typical example of a spectrum is shown in Figure \ref{fig:cs-spectrum}.
The bound-state energies are unchanged, the continuum rotates by
$-2 \theta$ around the origin, and resonances appear as isolated
eigenvalues in the fourth quadrant once $\theta$ is sufficiently large
to ``uncover'' them from the continuum.
Octopus supports calculations with complex scaling
for independent particles or
in combination with DFT and
selected
XC functionals\cite{Larsen:2013cw}.
This combination relies on complex-scaling the DFT energy functional.
The energy functional in Kohn--Sham DFT consists of several
terms that are all expressible as integrals of the density or the
wavefunctions.
The functional is complex-scaled by rotating the integration contour
of every term by $\theta$ in the complex plane.
The energy functional thereby expressible as
% Problem: with \ve r', the arrow overlaps with the apostrophe.
% This command fixes it, but maybe it isn't relevant if they change font anyway.
%\newcommand{\rprime}[0]{\ve r^{\,}{}'}
\newcommand{\rprime}[0]{\ve r'}
\begin{align}
E_\theta &= \ee^{-\ii2\theta}
\sum_n \int\dee\ve r\, \psi_{\theta n}(\ve r) \left(-\frac12 \nabla^2\right)
\psi_{\theta n}(\ve r)
+ \ee^{-\ii\theta} \frac12
\iint \dee \ve r \, \dee \rprime \,
\frac{n_\theta(\ve r)n_\theta(\rprime)}{\Vert\ve r - \rprime\Vert}\nonumber\\
&\quad+ E_\xc^\theta[n_\theta]
+ \int\dee \ve r\, v_{\mathrm{ext}}(\ve r \ee^{\ii \theta}) n_\theta(\ve r),
\end{align}
with the electron density
\begin{align}
n_\theta(\ve r) = \sum_n f_n \psi_{n \theta}^2(\ve r),
\end{align}
occupation numbers $f_n$, and complex-scaled Kohn--Sham states $\psi_{n \theta}(\ve r)$.
We also need to define the complex-scaled XC potential $E_\xc^\theta[n_\theta]$.
Note how wavefunctions $\psi_{\theta n}(\ve r)$ and density $n_\theta(\ve r)$
are complex, but no complex conjugation is performed of the left component in
matrix elements such as the density or kinetic energy as is the correct procedure
when calculating matrix elements of states that would have been purely real
in the unscaled case.
In standard DFT the Kohn--Sham equations
are obtained by taking the derivative of the energy functional with respect
to the wavefunctions. Solving the equations corresponds to searching
for a stationary point, with the idea that this
text minimizes the energy.
In our case we cannot minimize the energy functional as it is
complex-valued, but we can search for a stationary point in exactly the same
way as has previously been argued\cite{WM07}.
The complex-scaled versions
of the Kohn--Sham thereby become similar to the usual ones:
\begin{align}
\left[-\frac12 \ee^{-\ii2\theta}\nabla^2 + v_{\mathrm{eff}}^\theta(\ve r)
\right] \psi_\theta(\ve r) = \psi_\theta(\ve r) \epsilon_\theta.
\end{align}
The effective potential $v_{\mathrm{eff}}^\theta(\ve r)$ is the functional derivative
of the energy functional with respect to the density $n_\theta(\ve r)$, and therefore
consists of the terms
\begin{align}
v_{\mathrm{eff}}^\theta(\ve r) \equiv \fdiff{E}{n_\theta(\ve r)} =
v_\Ha^\theta(\ve r) + v_\xc^\theta(\ve r)
+ v_{\mathrm{ext}}(\ve r \ee^{\ii\theta})
\end{align}
with
your caption \begin{align}
v_\Ha^\theta(\ve r) &=
\ee^{-\ii\theta}\int\dee \ve r\, \frac{n_\theta(\ve r')}{\Vert \ve r'-\ve r\Vert},\\
v_\xc^\theta(\ve r) &= \fdiff{E_\xc^\theta[n_\theta]}{n_\theta(\ve r)}.
\end{align}
blahblah......
The complex-scaled Hartree potential is determined by solving the
Poisson equation
\begin{align}
E_\Ha^\theta = \ee^{-\ii\theta} \frac12
\iint \dee \ve r\, \dee \ve r'\,
\frac{\rho(\ve r)\rho(\ve r')}{\Vert\ve r - \ve r'\Vert}
\end{align}
The lowest-energy resonance of a system is then found by searching for
stationary points\cite{WM07} of the functional.
\cite{doi:10.1021/jz9001778,WW11} % daniel JPhysChemLett, PRL
....