Ask Hjorth Larsen edited Complex DFT.tex  over 9 years ago

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and lifetime.  Mathematically, resonances can be defined as poles of the scattering  matrix or cross-section at complex energies. energies.\cite{PhysRev.56.750,Hatano01022008}  If a pole is close to the real energy axis it will produce a large, narrow peak in the  cross-section of scattered continuum states around close to  that energy. Another way to create a resonance is to apply an  electric field strong enough to ionize the system through tunnelling.  Resonant states may temporarily capture incoming electrons or electrons  excited from bound states, making them important intermediate states  in many processes.Another way to create a resonance is to apply an  electric field strong enough to ionize the system through tunnelling.  %Resonances are typically seen in scattering experiments  %as a peak of given energy and width, with the width being proportional  %to the lifetime. For example a resonance will correspond a peak in  %the electron scattering cross section. A long-lived resonant state can be thought  %of as an ``almost bound state'', but the properties of resonant states are  %nevertheless very different, and different methods must be used to calculate them.  The defining characteristic of a resonant state is that it has an  outgoing component but not an incoming one.  Such states are often called Siegert  states\cite{PhysRev.56.750}. They can be determined by solving the time-independent Schrödinger  equation with the boundary condition that the wave must asymptotically  have the form% $r\phi(r) \sim \exp(+\ii k r)$ as $r \rightarrow \infty$.  \begin{align}  \phi(r) \sim \exp(\ii k r)/r\quad\textrm{as $r\rightarrow\infty$}. $r\rightarrow\infty$},  \end{align}  The where the  momentum $k$ is complex with and has a  negative imaginary part. This causes the state to diverge exponentially in space as $r\rightarrow\infty$. Its energy also has The state can further be ascribed a complex  energy, likewise with a  negative imaginary part, causing it to decayexponentially  over timeuniformly  at every point in space.  Since they have complex energies they are not eigenstates of any Hermitian operator,  and indeed do not belong to the Hilbert space.  This precludes the direct calculation of resonances with  the standard computational methods known from DFT. space uniformly.  The method Resonant states are not eigenstates  of \emph{complex scaling}\cite{aguilarcombes,Balslev:1971ez}  circumvents this problem by a transformation  which maps any Hermitian operator and   in particular do not reside within  the Hamiltonian to Hilbert space. This precludes their direct  calculation with the standard computational methods  from DFT. However it turns out that  a non-Hermitian operator  $\hat H_\theta = \hat R_\theta \hat H \hat R_{-\theta}$, where suitably chosen analytic  continuation of a Siegert state is localized, and this form can be used  to derive information from  the operator $\hat R_\theta$ state.  This  is the idea behond the  \emph{complex scaling}\cite{aguilarcombes,Balslev:1971ez} method where  states and operators are represented  by means of the transformation  \begin{align}  \hat R_\theta \psi(\ve r) = \ee^{\ii N \theta / 2} \psi(\ve r \ee^{\ii\theta}),  \end{align}  and where  $N$ is the number of spatial  dimensions in to  which the scaling operation is applied.  The parameter applied, and  $\theta$ is a fixed number that one must choose, with \emph{scaling angle} which deteremines  the original theorems proven for $0<\theta<\pi/4$. The spatial coordinates $\ve  r$ are rotated to $\ve r \ee^{\ii\theta}$ path  in the complex plane, and one  hence works in terms of plane along which  the analytic continuations of both states and  operators. continuation is taken.  The transformation maps the Hamiltonian to a non-Hermitian operator  $\hat H_\theta = \hat R_\theta \hat H \hat R_{-\theta}$.  Theidea of complex scaling is that for a suitable $\theta$,  the analytic continuation of the  Siegert states are \emph{localized}  instead $\psi(\ve r)$  of diverging,  and the original Hamiltonian  are square-integrable  eigenstates $\psi_\theta(\ve r)$  ofthe non-Hermitian  operator  $\hat H_\theta$. Importantly, H_\theta$, and their eigenvalues $\epsilon_0 - \ii\Gamma/2$  define  the matrix elements energy $\epsilon_0$ and width $\Gamma$  of localized states, the  resonance. More details can be found  inparticular  the energies, are independent many reviews  of $\theta$. This ensures all physical  bound-state characteristics complex scaling~\cite{simon1973resonances,doi:10.1146/annurev.pc.33.100182.001255,Ho19831}.  \begin{figure}  \centering  \includegraphics{fig-cs-spectrum}  \includegraphics{fig-cs-potential}  \caption{Spectrum (left)  of the untransformed one-dimensional complex-scaled single-particle  Hamiltonian with potential  $v(x) = 3(x^2 - 2) \ee^{-x^2 / 4}$ and $\theta=0.5$.  The lowest-energy resonance, here located close to the origin,  does not lie exactly on the real axis but has an  imaginary part of about $-10^{-5}$. Right: The potential (blue)  and the real (fully drawn) and imaginary (dotted) parts of the  two bound and three lowest resonant wavefunctions. For improved visualization,  the wavefunctions  are retained. vertically displaced by the real parts of their energies.}  \label{fig:cs-spectrum}  \end{figure}  A typical example of a spectrum of the transformed Hamiltonian $\hat H_\theta$  is shown in Figure \ref{fig:cs-spectrum}. The bound-state energies are unchanged, the continuum rotates by  $-2 \theta$ around the origin, and resonances appear as isolated  eigenvalues in the fourth quadrant once $\theta$ is sufficiently large  to ``uncover'' them from the continuum.  Importantly, matrix elements (and in  particular energies) of states are independent of $\theta$ as long as  the states are localized and well presented numerically --- this  ensures that all physical  bound-state characteristics of the untransformed Hamiltonian are retained.  Our implementation supports calculations with complex scaling   for independent particles or  in combination with DFT and  selected  XC functionals~\cite{Larsen:2013cw}.  This combination relies on complex-scaling the DFT energy functional. functionals\cite{Larsen:2013cw}.  The energy functional in Kohn--Sham DFT consists of several  terms that are all expressible as integrals of the density or the  wavefunctions. wavefunctions with the kinetic operator and various potentials.  The functional is complex-scaled as per the prescribed method  by rotating the real-space  integration contour of every term by $\theta$ in the complex plane.  This makes the functional expressible  The energy functional thereby then becomes  expressible as % Problem: with \ve r', the arrow overlaps with the apostrophe.  % At least when vectors are denoted by arrows.  % This command fixes it, but maybe it isn't relevant if they change font anyway.  %\newcommand{\rprime}[0]{\ve r^{\,}{}'}  \newcommand{\rprime}[0]{\ve r'} 

\end{align}  with the electron density  \begin{align}  n_\theta(\ve r) = \sum_n f_n \psi_{n \theta}^2(\ve \psi_{\theta n}^2(\ve  r), \end{align}  occupation numbers $f_n$, and complex-scaled Kohn--Sham states $\psi_{n \theta}(\ve $\psi_{\theta n}(\ve  r)$.We also need to define the complex-scaled XC potential $E_\xc^\theta[n_\theta]$.  Note how that  the wavefunctions $\psi_{\theta n}(\ve r)$ and density $n_\theta(\ve r)$ are complex, but no complex conjugation is performed of the left component in  matrixelements. This the the correct procedure  when calculating matrix  elements of states that would such as the density or kinetic energy  (the ``unscaled'' wavefunctions are assumed to  be purely real in since the system is finite, and the complex scaling transformation  subsequently affects the coordinates of left and right states equally, i.e.,  without complex conjugation).  The XC functional is complex-scaled by taking the analytic continuation  similarly to any other functional, and its exact form of course depends  on  the unscaled case. chosen approximation; see Ref.~\cite{Larsen:2013cw}.  In standard DFT the Kohn--Sham equations  are obtained by taking the derivative of the energy functional with respect  to the wavefunctions. Solving the equations corresponds to searching  for a stationary point, with the idea that this minimizes the energy.  In the present our  case we cannot minimize the energy functional as it is complex-valued, but we can search for a stationary point in exactly the same  way as has previously been argued\cite{WM07}.  The complex-scaled versions  of the Kohn--Sham equations  thereby become similar to the usual ones: \begin{align}  \left[-\frac12 \ee^{-\ii2\theta}\nabla^2 + v_{\mathrm{eff}}^\theta(\ve v_\theta(\ve  r) \right] \psi_\theta(\ve \psi_{\theta n}(\ve  r) = \psi_\theta(\ve \psi_{\theta n}(\ve  r) \epsilon_\theta. \epsilon_{\theta n}.  \end{align}  The effective potential $v_{\mathrm{eff}}^\theta(\ve $v_\theta(\ve  r)$ is the functional derivative of the energy functional with respect to the density $n_\theta(\ve r)$, and therefore  consists of the terms  \begin{align}  v_{\mathrm{eff}}^\theta(\ve v_\theta(\ve  r) \equiv \fdiff{E}{n_\theta(\ve r)} = v_\Ha^\theta(\ve r) + v_\xc^\theta(\ve r)   + v_{\mathrm{ext}}(\ve r \ee^{\ii\theta})  \end{align}  with where $v_{\mathrm{ext}}(\ve r \ee^{\ii\theta})$ may represent atomic  potentials as analytically  continued pseudopotentials, and where the Hartree potential  \begin{align}  v_\Ha^\theta(\ve r) &=  \ee^{-\ii\theta}\int\dee \ve r\, \rprime\,  \frac{n_\theta(\ve r')}{\Vert \ve r'-\ve r\Vert},\\  v_\xc^\theta(\ve r) &= \fdiff{E_\xc^\theta[n_\theta]}{n_\theta(\ve r)}. r\Vert}  \end{align}  blahblah......  The complex-scaled Hartree potential is determined by solving the Poisson equation defined by the complex density.  Together with the XC potential  \begin{align}  E_\Ha^\theta = \ee^{-\ii\theta} \frac12  \iint \dee \ve r\, \dee \ve r'\,  \frac{\rho(\ve r)\rho(\ve r')}{\Vert\ve r - \ve r'\Vert} v_\xc^\theta(\ve r) &= \fdiff{E_\xc^\theta[n_\theta]}{n_\theta(\ve r)},  \end{align}  this defines a self-consistency cycle very similar to ordinary  Kohn--Sham DFT although more care must be taken to occupy the correct states,  as they are no longer simply ordered by energy.  The lowest-energy resonance of a system is then found by searching for  stationary points\cite{WM07} of the functional.  \cite{Whitenack_2010,WW11} % daniel JPhysChemLett, PRL functional\cite{doi:10.1021/jz9001778,WW11}.  In practice one can obtain the correct complex-scaled form \begin{figure}   \includegraphics{ionization-He}  \caption{Ionization rate  of every  term by taking the derivative He atom in an electric field as a function  of the energy functional after imposing  the   ... field strength. From Ref.~\cite{Larsen:2013cw}}  \label{fig:cs-ionization-He}  \end{figure}  Figure \ref{fig:cs-ionization-He} shows calculated ionization rates of the He 1s state in a  uniform Stark-type electric field as a function of field strength.  In the limit of weak electric fields, the simple perturbative approximation  by Ammosov, Delone and Krainov,\cite{adk} which is depends  only on the ionization potential, approaches the accurate correlated reference  calculation by Scrinzi.\cite{PhysRevLett.83.706}  This demonstrates that the ionization rate is determined largely by the  ionization potential for weak fields. As the LDA is known to produce  inaccurate ionization potentials  due to its wrong asymptotic form at large distances, the LDA necessarily yields  inaccurate rates at low fields.  Meanwhile exact exchange, which is known to produce  accurate ionization energies, predicts ionization rates  much closer to the reference calculation. The key property   of the XC functional that allows accurate determination of decay rates  from complex-scaled DFT therefore appears to be that it must yield  accurate ionization potentials, which is linked to its ability  to reproduce the correct asymptotic form of the potential at large distances  from the system\cite{PhysRevA.49.2421}.