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Alexander Kloentrup edited The_above_figure_demonstrates_the__.tex
over 8 years ago
Commit id: e3d044c1e44a7f56e0786aa289558a046421353c
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The above figure demonstrates the how the basin speeds affect the length and height of the rebound. The equation relating these is: \begin{equation}
\frac{4\pi*\mu*Vbath^2L^2}{Vjet*(7.4/Rebath} \frac{4\pi \mu {V_{bath}}^{2} L^{2}}{V_{jet} ln{\frac{7.4}{Re_{bath}}}}\approx \sigma b^{2}Q^{2}
\end{equation}
Where q is the volumetric flow rate into the basin