deletions | additions       diff --git a/Introduction and Theory.tex b/Introduction and Theory.tex  index c24660f..1dcfbe0 100644  --- a/Introduction and Theory.tex  +++ b/Introduction and Theory.tex 
...
\par Using this photon polarization basis, the value for the inequality is given by  \[ S=E(a,b)-E(a,b^\prime)+E(a^\prime,b)+E(a^\prime,b^\prime) \]  \par where ${a,b,a^\prime,b^\prime}$ $(a,b,a^\prime,b^\prime)$  are polarization angles. The correlation between two angles is given by \[ E(a,b)=\frac{N(a,b)+N(a_\perp,b_\perp)-N(a_\perp,b)-N(a,b_\perp)}{N(a,b)+N(a_\perp,b_\perp)+N(a_\perp,b)+N(a,b_\perp)} \]  where the perpendicular angles are rotated by $\frac{\pi}{2}$. Thus, only 16 seperate measurements had to be taken for the $\psi_+$ and $\psi_-$ states. The angles were chosen such that the value of $S$ was maximized. For $\psi_+$, ${a,b,a^\prime,b^\prime} $(a,b,a^\prime,b^\prime)  = {0,67.5,45,22.5}$ (0,67.5,45,22.5)$, and for $\psi_-$, $(-45,-22.5,0,22.5)$.