Alec Aivazis edited kinematics.tex  almost 10 years ago

Commit id: feb6a905c1af3e81ccd69e7619a0aa9e415e3ecc

deletions | additions      

       

\mathbf{\mu^{+}}^2 = \mathbf{\pi^{+}}^2 - 2 ( \mathbf{\pi^{+}} \cdot \mathbf{\nu_{\mu}} ) - \mathbf{\nu_{\mu}}^2  \end{equation}  It is important to note that since the magnitude of a 4-vector is a Lorenz invariant, for any energy-momentum 4 vector, $\mathbf{p}$, vector $\mathbf{p}$  where \begin{equation}  \mathbf{p} = (E, \vec{p} )