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Alec Aivazis edited kinematics_flux.tex
almost 10 years ago
Commit id: d26a02ba1f754d92b37ac7a2aaa23809dc3d9cca
deletions | additions
diff --git a/kinematics_flux.tex b/kinematics_flux.tex
index 0e5f05e..b68bb01 100644
--- a/kinematics_flux.tex
+++ b/kinematics_flux.tex
...
\frac{d^2 N}{d \cos \theta d E_{\nu}} = \frac{d^2 N}{d \cos \theta' d E_{\nu}} \frac{d \cos \theta'}{d \cos \theta}
\end{equation}
From, To understand the behavior of the nuetrino flux, notice that
\begin{equation}
\cos \theta & = \sqrt{1 - \sin^2 \theta}
\end{equation}
and from equation \ref{eq:tan}
\begin{equation}
\sin \theta' \approx \frac{E_{\nu}}{E_{\nu}'} \tan \theta
\end{equation}
Therefore,
\begin{equation}
\begin{split}
\cos \theta' & \approx \sqrt{1-\frac{E_{\nu}^2}{E_{\nu}^2}\tan^2 \theta} \\
& = \sqrt{1-\frac{E_{\nu}^2}{E_{\nu}^2} \left(\frac{1}{\cos^2 \theta}-1\right)}
\end{split}
\end{equation}