Alec Aivazis edited kinematics.tex  almost 10 years ago

Commit id: 4b2888cc1f11ed15c8eeb453e13cfff6f43950da

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Plugging this into equation \ref{energy-momentum-expanded} we get  \begin{equation}  m_{\mu}^2 = m_{pi}^2 m_{\pi}^2  - 2(\pi \cdot \nu_{\mu}) \end{equation}