Alec Aivazis edited kinematics.tex  almost 10 years ago

Commit id: 2fce1446fe05dc19737c0a65b4a4053d803341f5

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\mathbf{\pi^{+}} = \mathbf{\mu^{+}} + \mathbf{\nu_{\mu}}  \end{equation}  Where $\mathbf{\pi^{+}}$, $\mathbf{\mu^{+}}$, and $\mathbf{\nu_{\mu}}$ are the energy-momentum 4-vectors. It is important to note that since $\mid \mathbf{p} \mid^2$ is a Lorentz invariant, where p $\mathbf{p}$  is any 4-vector,one can always boost to the rest frame of the particle where $\vec{p} = 0$. Since in natural units \begin{equation}  E^2 = \vec{p}^2 + m^2