Investment Math edited Calculations_The_value_function_is__.md  almost 8 years ago

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\[V(p)=p^{-\pi}\exp(2\pi (p-1)),\, 1/2 \lt p \lt 1,\]  \[V(p)=p^{\pi},\, p \geq 1.\]  The trading function is obtained by differentiation as usual:  \[n(p)=\pi (-1+2p)p^{-\pi-1}\exp(2\pi(p-1)),\, 1/2 \lt  p \lt 1,\] \[n(p)=\pi p^{\pi-1},\, p \geq 1.\]