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Using \ref{fig:NeonAnalysis} and Eq. \ref{eq:lowestlevel}, we plugged in x to be 0.5 to find the excitation level for each of the linear fits shown in the plot. This generated a excitation energy of $19.4993 \pm 0.6$ eV. However, according to the NIST website, this number is closer to the second excitation level (Fig. \ref{fig:NeonEnergyLevels}.) \\  When we subtract the background from Fig. \ref{fig:NeonAnalysis}, the first excitation level does not appear because we are subtracting a quadratic function. This could be a reason that why we only measure the second energy level. Another possible reason could be that we do not have enough data points. So when we subtract the quadratic function, we lose some of the dips since there are not enough data points to produce a slope of 0 on either side of the dip. Therefore, we only measured the second energy level after subtracting the background. background.However, this can not be the case because we derived Eq. \ref{eq:lowestlevel} by setting $E_a$ equal to the lowest energy level. So, we conclude that we our data does not match the first excitation level of around 16.62eV.