deletions | additions       diff --git a/In_order_to_better_observe__.tex b/In_order_to_better_observe__.tex  index c2ff26d..ed61eca 100644  --- a/In_order_to_better_observe__.tex  +++ b/In_order_to_better_observe__.tex 
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To recap the two voltages that are being measured, there is the anode voltage which measures the electrons hitting the last plate in the tube and there is the accelerating voltage that measures the voltage applied to the system.   \textbf{NOT TRUE: only one voltage is being physically measured: the accelerating voltage for the electrons. The other quantity being measured is a current: the electron current from cathode to anode. You are confusing what is measured in your apparatus --- the Frank hertz tube --- with what is RECORDED by the computer. Just because the output of an instrument that you measure with a computer happens to be a voltage doesn't mean that what the instrument measured was a voltage. according to the table below, if the computer \textit{recorded} a voltage \textit{voltage}  of 1 V, then it meant that the cathode to anode current \textit{current}  that was \textit{measured} was 5 nA} In order to obtain more information on the quantum nature of atoms, the anode current plotted against the accelerating voltage would provide a general idea of the excited energy levels.