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\section{Analysis}  \subsection{Neon Experiment}   E= 0.5 Ea   Using \ref{fig:NeonAnalysis} and Eq. \ref{eq:lowestlevel}, we plugged in x to be 0.5 to find the excitation level for each of the linear fits shown in the plot. This generated a excitation energy of $19.4993 \pm 0.6$ eV. However, according to the NIST website, this number is closer to the second excitation level (Fig. \ref{fig:NeonEnergyLevels}. \\