Ning Zhu edited subsection_Slope_Fit_Calculation_begin__.tex  over 8 years ago

Commit id: e19b7b6c9af4b7f472c0f9c9a326461573bd9947

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%From Figure \ref{fig:directmethoddata}:   V&=&\frac{0.021\cdot (1+cos(\frac{2\pi\cdot(\theta-162)}{180}))}{2}\\  %Taking the derivative at $\theta=117$ degrees:  \frac{\Delta V}{\Delta \theta}&=&\frac{0.21}{2}\cdot(-sin(2\frac{\pi}{180}(-45)))=0.21V\\ \theta}&=& 0.21\cdot(-sin(2\frac{\pi}{180}(-45)))=0.21V\\  \frac{\Delta\theta}{\Delta B}&=&\frac{\Delta V}{\Delta B} \cdot \frac{\Delta \theta}{\Delta V}=0.443\frac{V}{T}\cdot\frac{1 radian}{0.21V}=2.1095\frac{radians}{T}\\  V_{c}&=&\frac{1}{L}\cdot \frac{\Delta\theta}{\Delta B}=\frac{1}{0.1}\cdot2.1095\frac{radians}{T}=21.095\frac{radians}{T \cdot m}  \end{eqnarray}