deletions | additions       diff --git a/subsection_Slope_Fit_Calculation_From__.tex b/subsection_Slope_Fit_Calculation_From__.tex  index 403c7c1..5c1c023 100644  --- a/subsection_Slope_Fit_Calculation_From__.tex  +++ b/subsection_Slope_Fit_Calculation_From__.tex 
...
\subsection{Slope Fit Calculation}  \begin{eqnarray}  From Figure \ref{fig:VB}  $$V=0.000443B+0.127$$ $$V&=&0.000443B+0.127$$\\  Therefore:  $$\frac{\Delta V}{\Delta B}=0.000443\frac{V}{mT}=0.443\frac{V}{T}$$ B}&=&0.000443\frac{V}{mT}=0.443\frac{V}{T}$$\\  From Figure \ref{fig:directmethoddata}:   $$V=\frac{0.021\cdot (1+cos(\frac{2\pi\cdot(\theta-162)}{180}))}{2}$$ $$V&=&\frac{0.021\cdot (1+cos(\frac{2\pi\cdot(\theta-162)}{180}))}{2}$$\\  Taking the derivative at $\theta=117$ degrees:  $$\frac{\Delta V}{\Delta \theta}=\frac{0.21}{2}\cdot(-sin(2\frac{\pi}{180}(-45)))=0.21V$$ \theta}&=&\frac{0.21}{2}\cdot(-sin(2\frac{\pi}{180}(-45)))=0.21V$$\\  $$\frac{\Delta\theta}{\Delta B}=\frac{\Delta B}&=&\frac{\Delta  V}{\Delta B} \cdot \frac{\Delta \theta}{\Delta V}=0.443\frac{V}{T}\cdot\frac{1 radian}{0.21V}=2.1095\frac{radians}{T}$$  $$V_{c}=\frac{1}{L}\cdot radian}{0.21V}=2.1095\frac{radians}{T}$$\\  $$V_{c}&=&\frac{1}{L}\cdot  \frac{\Delta\theta}{\Delta B}=\frac{1}{0.1}\cdot2.1095\frac{radians}{T}=21.095\frac{radians}{T \cdot m}$$ \end{eqnarray}