deletions | additions       diff --git a/subsection_Direct_Fit_Method_We__.tex b/subsection_Direct_Fit_Method_We__.tex  index 4338a63..d571225 100644  --- a/subsection_Direct_Fit_Method_We__.tex  +++ b/subsection_Direct_Fit_Method_We__.tex 
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\begin{equation}  c_v=\frac{1}{L}\frac{d\theta}{dB}  \end{equation}  We can't guarantee that we turn the polarizer to the angel we want exactly, and we estimate there will be an uncertainty of 0.05 degrees in d$\theta$. By plugging in the maximum(4.05 degrees) and minimum(3.95 degrees) into our calculation, we are able to get an uncertainty of the Verdet constant.  21.23  where L is the length of the solenoid, which is 0.1m in our case.\newline  In this way, we get:  $$V_{c}=20.7\pm 0.845\frac{radians}{T $$V_{c}=20.96\pm 0.2650\frac{radians}{T  \cdot m}$$ %We fit our data to a function of the form $V=V_{0}sin(\phi)^2$. We could find $\frac{\Delta V}{\delta \phi}$ by taking the derivative and using φ=45 degrees, and we could find ΔV by taking the difference of the voltage read by the photodetector when the laser is on (at maximum voltage read) and off. We could then find Δφ by calculating how much the angle of maximum transmission through the polarizer shifter. With all of this information, we could find dB/dφand use the equation $\frac{\Delta B}{\Delta \phi}=\frac{1}{L}\times\frac{1}{C_{v}}$ to find the Verdet constant of the glass tube.