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Ning Zhu edited begin_eqnarray_c_v_frac_1__.tex
over 8 years ago
Commit id: 06a7fae349a0a7e7d57111f7edec1de5c33cba68
deletions | additions
diff --git a/begin_eqnarray_c_v_frac_1__.tex b/begin_eqnarray_c_v_frac_1__.tex
index 8383fbf..57426b5 100644
--- a/begin_eqnarray_c_v_frac_1__.tex
+++ b/begin_eqnarray_c_v_frac_1__.tex
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method 1& = & \frac{1}{L}\frac{\Delta \theta}{\Delta B} \\
method 2& = & \frac{1}{L}\left(\frac{d\theta}{dV_{pd}}\right)_{at ?}\frac{dV_{pd}}{dB}\\
method 3& = & \frac{1}{L}\left(\frac{d\theta}{dV_{pd}}\right)_{at ?} \frac{V_{pd, RMS}}{B_{RMS}}
\end{eqnarray}
\subsection{Direct Method Calculation}
\begin{eqnarray}
V_{c}&=&\frac{1}{L}\times \frac{\Delta\theta}{\Delta B}\\
%$$\frac{\Delta\theta}{\Delta B}=\frac{\Delta V}{\Delta B} \times \frac{\Delta \theta}{\Delta V}$$
\theta_{B}&=&104 degrees; \theta_{0}=108 degrees\\
\Delta\theta&=&\theta_{B}-\theta_{0}=-0.069 radians\\
\Delta B&=&-3A\times 11.1\frac{mT}{A}=-33.3mT\\
\frac{\Delta\theta}{\Delta B}&=&\frac{-0.069radians}{-33.3mT}=0.00207\frac{radians}{mT}=2.07\frac{radians}{T}\\
V_{c}&=&\frac{1}{L}\times \frac{\Delta\theta}{\Delta B}=\frac{1}{0.1m}\times 2.07\frac{radians}{T}=20.7\frac{radians}{T \cdot m}
\end{eqnarray}