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3. Lock-in Method  $$I_{coil_dc}=0.6137\times V_{coil_dc}$$  $$B=11.1\times\frac{mT}{A}\times I$$  $$V_{Photodiode}=\frac{V_{output}\times1.11}{500\times2\times10\times1}$$ $$Gain=G_{preamplifier}\times G_{filter}\times G{lock-in amplifier}\times G_{lowpass filter}=500\times2\times10\times1=10000$$  $$V_{Photodiode}=\frac{V_{output}\times1.11}{10000}$$