Ning Zhu edited Figures.tex  over 8 years ago

Commit id: cd1bbaa4262247bcc95a3e9acfccb0f756d6d9cd

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$$\frac{\Delta\theta}{\Delta B}=\frac{-0.069radians}{-33.3mT}=0.00207\frac{radians}{mT}=2.07\frac{radians}{T}$$  $$V_{c}=\frac{1}{L}\times \frac{\Delta\theta}{\Delta B}=\frac{1}{0.1m}\times 2.07\frac{radians}{T}=20.7\frac{radians}{T*m}$$  2. Slope Fit Fit\newline  As shown in Figure 2:  $$V=0.000443B+0.127$$  Therefore: 

$$\frac{\Delta V}{\Delta \theta}=\frac{0.21}{2}\times(-sin(2\frac{\pi}{180}(-45)))=0.21V$$  $$\frac{\Delta\theta}{\Delta B}=\frac{\Delta V}{\Delta B} \times \frac{\Delta \theta}{\Delta V}=0.443\frac{V}{T}\times\frac{1 radian}{0.21V}=2.1095\frac{radians}{T}$$  $$V_{c}=\frac{1}{L}\times \frac{\Delta\theta}{\Delta B}=\frac{1}{0.1}\times2.1095\frac{radians}{T}=21.095\frac{radians}{T*m}$$  3. Lock-in Method  $$I_{coil_dc}=0.6137\times V_{coil_dc}$$  $$B=11.1\times\frac{mT}{A}\times I$$  $$V_{Photodiode}=\frac{V_{output}\times1.11}{500\times2\times10\times1}$$