Ning Zhu edited Figures.tex  over 8 years ago

Commit id: bf404863d3f1fbe8d9d7e7974e1cd265d5ca21af

deletions | additions      

       

Therefore:  $$\frac{\Delta V}{\Delta B}=0.000443\frac{V}{mT}=0.443\frac{V}{T}$$  As shown in Figure 1:   $$V=\frac{0.021\times (1+cos(\frac{2\pi\times(\theta-162)}{180}))}{2}$$ $$\frac{\Delta V}{\Delta\theta}=\frac{0.21}{2}\times(-sin(2\frac{\pi}{180}(-45)))$$