Ning Zhu edited Figures.tex  over 8 years ago

Commit id: a2c4fa8d8c88089cdf51a6dd1bee0acd495585d5

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$$V=\frac{0.021\times (1+cos(\frac{2\pi\times(\theta-162)}{180}))}{2}$$  Taking the derivative at $\theta=117$ degrees:  $$\frac{\Delta V}{\Delta \theta}=\frac{0.21}{2}\times(-sin(2\frac{\pi}{180}(-45)))=0.21V$$  $$\frac{\Delta\theta}{\Delta B}=\frac{\Delta V}{\Delta B} \times \frac{\Delta \theta}{\Delta V}=0.443\frac{V][T}\times\frac{1 V}=0.443\frac{V}{T}\times\frac{1  radian}{0.21V}=2.1095\frac{radians}{T}$$ $$V_{c}=\frac{1}{L}\times \frac{\Delta\theta}{\Delta B}=\frac{1}{0.1}\times2.1095\frac{radians}{T}=21.095\frac{radians}{T*m}$$