Ning Zhu edited Figures.tex  over 8 years ago

Commit id: 9c0b967df222384b6ad1c7634bef058593a0065c

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Therefore:  $$\frac{\Delta V}{\Delta B}=0.000443\frac{V}{mT}=0.443\frac{V}{T}$$  As shown in Figure 1:   $$\frac{\Delta V}{\Delta \theta}=\frac{0.021\times $$V=\frac{0.021\times  (1+cos(\frac{2\pi\times(\theta-162)}{180}))}{2}$$