Ning Zhu edited Figures.tex  over 8 years ago

Commit id: 5b6187fad74040b610dc67b629bafa0ec13d8039

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$$\Delta\theta=\theta_{B}-\theta_{0}=-0.069 radians$$  $$\Delta B=-3A\times 11.1\frac{mT}{A}=-33.3mT$$  $$\frac{\Delta\theta}{\Delta B}=\frac{-0.069radians}{-33.3mT}=0.00207\frac{radians}{mT}=2.07\frac{radians}{T}$$  $$V_{c}=\frac{1}{L}\times \frac{\Delta\theta}{\Delta B}=\frac{1}{0.1m}\times 2.07\frac{radians}{T}=20.7\frac{1}{T*m}$$ 2. Slope Fit  As shown in Figure 2:  $$V=0.000443B+0.127$$  Therefore:  $$\frac{\Delta V}{\Delta B}=0.000443\frac{V}{mT}=0.443\frac{V}{T}  As shown in Figure 1:   $$V=\frac{0.021\times (1+cos(\frac{2\pi\times(\theta-162)}{180}))}{2}$$